Ndef simple channel expansion question

Questions
17

Well, it works automagically in SynthDef context. To explain slightly more, it turned out that

Ndef(\jc, Ndef(\ar2))

has exactly the same call chain from a point onwards as if you had written

Ndef(\jc, { Ndef(\ar2).value })

Which means the latter is a function source to be eval’d in ProxySynthDef context, which due to the “magic” of BusPlug.value does

Ndef(\jc, { Ndef(\ar2).ar })

So, even the deceptively simple “data copy” Ndef(\jc, Ndef(\ar2)) is treated as “identity math expression” and actually implemented by compiling a new ProxySynthDef that does the copying.