Combining Pfunc and Pswitch?

Questions
#1

Hello I’d like to have a Pattern, Pswitch, which depends on an array, here ~a, which whenever it gets changed, the Pswitch should adapt to this. Usually one could do it with Pfunc. It would look like this:

~a = [1,0,1];
(
Pbind(
	\dur, 0.3,
	\amp, 0.15 * Pswitch(~a,Pseries(0,1)).trace,
).play;
)
//changing this should change the rhythm, similiar to Pfunc
~a = [1,0,0]; 
~a = [1,0,1];

I mean after all, one could do it like this, but i feel like i’d prefere a solution in the upper style:

(
Pbind(
	\dur, 0.3,
	\amp_helper, Pseq([0,1,2],inf),
	\amp, Pfunc{|e| ~a[e[\amp_helper]]},
).play;
)
~a = [1,0,0]; 
~a = [1,0,1];

I’m glad for any hints. thank you!

#2

I mean the main question is, is there a way to put a Pseq into a Pfunc? Or a way for put a Pfunc into the Pswitch?

#3

Pfunc is expected to return a value, not a pattern so you cannot let it return a Pseq.
You are looking for Plazy instead.

~a = [1,0,1];
(
Pbind(
	\dur, 0.3,
	\amp, 0.15 * Pn(Plazy({Pseq(~a, 1)}), inf),
).play;
)
//changing this should change the rhythm, similiar to Pfunc
~a = [1,0,0]; 
~a = [1,0,1];
1 Like
#4

Yes thats it!! I wish it would’ve been refered on the Pfunc help page. Anyhow Thank you very much!!

#5
1 Like